-0.02x^2+0.8x+37=0

Solution for -0.02x^2+0.8x+37=0 equation:

-0.02x^2+0.8x+37=0

a = -0.02; b = 0.8; c = +37;
Δ = b2-4ac
Δ = 0.82-4·(-0.02)·37
Δ = 3.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{3.6}}{2*-0.02}=\frac{-0.8-\sqrt{3.6}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{3.6}}{2*-0.02}=\frac{-0.8+\sqrt{3.6}}{-0.04}
$